Travis
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- Jul 14, 2016
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"Hydrogen atoms in this position are exceptionally active and can reduce the Carbonyl initiators as well as the free radical carriers of the oxidation chains." ―William Koch MD, PhD
William Koch appears to be correct about the α-carbon; his Ph.D. was in chemistry. Below is what Timothy Soderberg has to say about the hydrogen on the α-carbon:
"The key concept to recall from what we have learned about acidity and basicity in organic chemistry, and to keep in mind throughout this discussion, is that α-protons (in other words, protons on α-carbons) are weakly acidic. Loss of an α-proton forms an enolate - a species in which a negative formal charge is delocalized between a carbon and an oxygen." ―Soderberg
"Let's review what we learned in section 7.6A about the acidity of a proton on an α-carbon and the structure of the relevant conjugate base, the enolate ion. Remember that this acidity can be explained by the fact that the negative charge on the enolate conjugate base is delocalized by resonance to both the α-carbon and the carbonyl oxygen." ―Soderberg
"Let's review what we learned in section 7.6A about the acidity of a proton on an α-carbon and the structure of the relevant conjugate base, the enolate ion. Remember that this acidity can be explained by the fact that the negative charge on the enolate conjugate base is delocalized by resonance to both the α-carbon and the carbonyl oxygen." ―Soderberg
➫ Soderberg, Timothy. "Organic chemistry with a biological emphasis." (2016).
Its fashionable to call hydrogen atoms (·H) without their electron simply a proton (H⁺), because this is what they usually are. But this is actually incorrect, as hydrogen has three natural isotopes: hydrogen (¹H), deuterium (²H), and tritium (³H). This means: When referring to the naked nuclei of hydrogen as "protons," you are wrong about 0.0156% of the time—when its a proton and a neutron.. . ..or sometimes even two.
Koch never ceases to amaze.. . ..and doesn't fall for that trap!
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